Optimal. Leaf size=108 \[ \frac{3 e^3 \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{e \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac{\left (d^2-e^2 x^2\right )^{5/2}}{5 d x^5}-\frac{3 e^5 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )}{8 d} \]
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Rubi [A] time = 0.0629703, antiderivative size = 108, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {807, 266, 47, 63, 208} \[ \frac{3 e^3 \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{e \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac{\left (d^2-e^2 x^2\right )^{5/2}}{5 d x^5}-\frac{3 e^5 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )}{8 d} \]
Antiderivative was successfully verified.
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Rule 807
Rule 266
Rule 47
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{(d+e x) \left (d^2-e^2 x^2\right )^{3/2}}{x^6} \, dx &=-\frac{\left (d^2-e^2 x^2\right )^{5/2}}{5 d x^5}+e \int \frac{\left (d^2-e^2 x^2\right )^{3/2}}{x^5} \, dx\\ &=-\frac{\left (d^2-e^2 x^2\right )^{5/2}}{5 d x^5}+\frac{1}{2} e \operatorname{Subst}\left (\int \frac{\left (d^2-e^2 x\right )^{3/2}}{x^3} \, dx,x,x^2\right )\\ &=-\frac{e \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac{\left (d^2-e^2 x^2\right )^{5/2}}{5 d x^5}-\frac{1}{8} \left (3 e^3\right ) \operatorname{Subst}\left (\int \frac{\sqrt{d^2-e^2 x}}{x^2} \, dx,x,x^2\right )\\ &=\frac{3 e^3 \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{e \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac{\left (d^2-e^2 x^2\right )^{5/2}}{5 d x^5}+\frac{1}{16} \left (3 e^5\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{d^2-e^2 x}} \, dx,x,x^2\right )\\ &=\frac{3 e^3 \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{e \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac{\left (d^2-e^2 x^2\right )^{5/2}}{5 d x^5}-\frac{1}{8} \left (3 e^3\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{d^2}{e^2}-\frac{x^2}{e^2}} \, dx,x,\sqrt{d^2-e^2 x^2}\right )\\ &=\frac{3 e^3 \sqrt{d^2-e^2 x^2}}{8 x^2}-\frac{e \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac{\left (d^2-e^2 x^2\right )^{5/2}}{5 d x^5}-\frac{3 e^5 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )}{8 d}\\ \end{align*}
Mathematica [A] time = 0.0671693, size = 133, normalized size = 1.23 \[ -\frac{-24 d^4 e^2 x^2-35 d^3 e^3 x^3+24 d^2 e^4 x^4+15 d e^5 x^5 \sqrt{1-\frac{e^2 x^2}{d^2}} \tanh ^{-1}\left (\sqrt{1-\frac{e^2 x^2}{d^2}}\right )+10 d^5 e x+8 d^6+25 d e^5 x^5-8 e^6 x^6}{40 d x^5 \sqrt{d^2-e^2 x^2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.074, size = 158, normalized size = 1.5 \begin{align*} -{\frac{1}{5\,d{x}^{5}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}-{\frac{e}{4\,{d}^{2}{x}^{4}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}+{\frac{{e}^{3}}{8\,{d}^{4}{x}^{2}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}+{\frac{{e}^{5}}{8\,{d}^{4}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{3}{2}}}}+{\frac{3\,{e}^{5}}{8\,{d}^{2}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}-{\frac{3\,{e}^{5}}{8}\ln \left ({\frac{1}{x} \left ( 2\,{d}^{2}+2\,\sqrt{{d}^{2}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}} \right ) } \right ){\frac{1}{\sqrt{{d}^{2}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.88028, size = 203, normalized size = 1.88 \begin{align*} \frac{15 \, e^{5} x^{5} \log \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{x}\right ) -{\left (8 \, e^{4} x^{4} - 25 \, d e^{3} x^{3} - 16 \, d^{2} e^{2} x^{2} + 10 \, d^{3} e x + 8 \, d^{4}\right )} \sqrt{-e^{2} x^{2} + d^{2}}}{40 \, d x^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 9.53821, size = 785, normalized size = 7.27 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.31877, size = 497, normalized size = 4.6 \begin{align*} \frac{x^{5}{\left (\frac{5 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )} e^{10}}{x} - \frac{10 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{2} e^{8}}{x^{2}} - \frac{40 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{3} e^{6}}{x^{3}} + \frac{20 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{4} e^{4}}{x^{4}} + 2 \, e^{12}\right )} e^{3}}{320 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{5} d} - \frac{3 \, e^{5} \log \left (\frac{{\left | -2 \, d e - 2 \, \sqrt{-x^{2} e^{2} + d^{2}} e \right |} e^{\left (-2\right )}}{2 \,{\left | x \right |}}\right )}{8 \, d} - \frac{{\left (\frac{20 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )} d^{4} e^{38}}{x} - \frac{40 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{2} d^{4} e^{36}}{x^{2}} - \frac{10 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{3} d^{4} e^{34}}{x^{3}} + \frac{5 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{4} d^{4} e^{32}}{x^{4}} + \frac{2 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )}^{5} d^{4} e^{30}}{x^{5}}\right )} e^{\left (-35\right )}}{320 \, d^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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